A bicyclist of mass 68 kg rides in a circle at a speed of 3.9 m/s. If the radius of the circle is 6.5 m, what is the centripetal force on the bicyclist?A.41 N B.159 N C.179 D.92 N

Question

24-02-2017
Physics

contestada

A bicyclist of mass 68 kg rides in a circle at a speed of 3.9 m/s. If the radius of the circle is 6.5 m, what is the centripetal force on the bicyclist?A.41 N B.159 N C.179 D.92 N

Respuesta :

Otras preguntas

What is the main disadvantage of a flat map? A Flat maps can't be made large enough that land masses appear the correct size. B Flat maps distort the shapes and

Do you think landowners should be compensated for their loss by the federal government for habitat conservation of endangered species?

In rhombus LMNO, diagonals top enclose L N end enclose and top enclose M O end enclose intersect at P. If the measure of angle L P M is represented by 2x + 70.

If all the members of a team are juniors or seniors, and if the ratio of juniors to seniors on the team is 3:5, what percent of team members are seniors?

PLEASSSSSSSSSSSEEEEEEEE HELPPP IM BEGGING SOMEONE PLEASEEEEEEEE PLEASEEEEEEEEEEE HELPPPP

Identify the isoelectronic elements. i. Cl-, F-, Br-, I-, At- ii. Ne, Ar, Kr, Xe, He iii. N3-, S2-, Br-, Cs+, Sr2+ iv. N3-, O2-, F-, Na+, Mg2+ v. Li+, Na+, K+,

What is the most significant challenge for organisms that live in estuaries? O A. Changing nutrient levels O B. Changing water temperatures O C. Changing water

factorise fully 3r+6r2

If c is the number of cats, which variable expression represents the phrase below? The sum of the number of cats and 15 dogs A. c•15 B. C+15 C. C-15 D.C/15

maraming bilang ng patalastas o iba pang elemento na hindi kasama sa mismong programa na sunod sunod na pinapatugtog a.mixing b.clutter c.playlist d.band

dexteright02 dexteright02 · Answer 1 · 2017-02-24T22:24:11+01:00

Data:
Centripetal Force = ? (Newton)
m (mass) = 68 Kg
s (speed) = 3.9 m/s
R (radius) = 6.5 m

Formula:
[tex] F_{centripetal\:force} = \frac{m*s^2}{R} [/tex]

Solving:
[tex] F_{centripetal\:force} = \frac{m*s^2}{R} [/tex]
[tex]F_{centripetal\:force} = \frac{68*3.9^2}{6.5}[/tex]
[tex]F_{centripetal\:force} = \frac{68*15.21}{6.5}[/tex]
[tex]F_{centripetal\:force} = \frac{1034.28}{6.5}[/tex]
[tex]\boxed{\boxed{F_{centripetal\:force} = 159.12\:N}}[/tex]
Answer:
B.159 N