Respuesta :

dexteright02
Data:
Molar Mass of CH3OH = 32.04 g/mol
[tex]9.66*10^{24}\:molecules\:of\:methanol=96.6*10^{23}\:molecules\:of\:methanol[/tex]

Solving: According to the Law Avogradro, we have in 1 mole of a substance, 6.02x10²³ atoms/mol or molecules

1 mol -------------------- 6.02*10²³ molecules
y mol -------------------- 96.6*10²³ molecules

6.02*10²³y = 96.6*10²³ 
[tex]y = \frac{96.6*\diagup\!\!\!\!\!\!10^{\diagup\!\!\!\!\!\!23}}{6.02*\diagup\!\!\!\!\!\!10^{\diagup\!\!\!\!\!\!23}} [/tex]
[tex]\boxed{y \approx 16.04\:mol}[/tex]


Solving: Find the mass value now

32.04 g ----------------- 1 mol of CH3OH
x g ------------- 16.04 mol of CH3OH

[tex]x = 32.04*16.04[/tex]
[tex]\boxed{\boxed{x = 513.92\:g}}\end{array}}\qquad\quad\checkmark[/tex]

Answer:
The mass is 513.92 grams