Respuesta :
[tex]y=-\frac{1}{2}(x+5)^2-2\\
y=-\frac{1}{2}(x^2+10x+25-2)\\
y=-\frac{1}{2}(x^2+10x+23)\\
[/tex]
this is not factorable so you must apply the quadratic formula and you'll end up with
x=-5-2i
x=-5+2i
this is not factorable so you must apply the quadratic formula and you'll end up with
x=-5-2i
x=-5+2i
frst opening formula : (a+b)^2=a^2+b^2+2ab
=-1/2[x^2+25+10x]-2
=-(x^2/2)-(25/2) -(5x)-(2) 0r =-1/2[x^2+25+10x+4]
=-1/2[x^2+10x+29]
=-1/2[x^2+25+10x]-2
=-(x^2/2)-(25/2) -(5x)-(2) 0r =-1/2[x^2+25+10x+4]
=-1/2[x^2+10x+29]