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A dog breed has a pair of alleles that determine curly hair (
c. versus straight hair (
c. given allele frequencies of c = 0.1 and c = 0.9, solve the hardy-weinberg equation to determine the expected frequencies of individuals in the population having genotypes cc, cc, and cc

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MissPhiladelphia
The hardy-weinberg equation is
p2 + 2pq + q2 = 1
where are already given with
c = 0.1 and C = 0.9
SO
p2 = 0.9^2
p2 = 0.81
q2 = 0.01
0.81 + 2pq - 0.01 = 1
2pq = 0.18
The answers are
CC = 0.81
cc = 0.01
Cc = 0.18
mickymike92

Based on the the Hardy-Weinberg equilibrium, the frequencies of individuals in population are 0.81, 0.01 and 0.18.

What is the Hardy-Weinberg equilibrium equation?

The Hardy-Weinberg equilibrium equation is used to determine the frequencies of individuals in a population at equilibrium.

The hardy-weinberg equation is given as

  • p^2 + 2pq + q^2 = 1

where

  • p^2 is frequency of the h0m0zygous dominant individuals
  • q^2 is the frequency of the h0m0zygous recessive individuals.

Given:

c = 0.1 and C = 0.9

Then;

p^2 = 0.9^2

p^2 = 0.81

Also;

q^2 = 0.1^2

q^2 = 0.01

Then, substituting the values in the Hardy-Weinberg equation:

0.81 + 2pq - 0.01 = 1

2pq = 0.18

Therefore, the frequencies of individuals in population are 0.81, 0.01 and 0.18.

Learn more about Hardy-Weinberg equation at: https://brainly.com/question/5028378

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