the components of velocity
are Vh ( horizontal) = 2.2 cos 45 and vertical Vv = 2.2 sin 45
to find the time when he lands we use
s = ut + 0.5at^2 where u = intial velocity , s = height, t = time and a = acce;eration due to gravity.
so
50 = 2.2sin45 t + 0.5*32*t^2
50 = 1.5556 t + 16t^2
16t^2 + 1.5556t - 50 = 0
t = 1.72 seconds
horizontal distance travelled = velocity * t = vh * t
=
2.2 cos 45 * 1.72 = 2.68 feet
