Respuesta :
let r=(x,y)
m=(r+s)/2
(1,3)=([x+8]/2 , [y+3]/2)
a) 1 = (x+8)/2
2 =x+8
x = -6
b) 3 = (y+3)/2
6 = y+3
y = 3
m=(r+s)/2
(1,3)=([x+8]/2 , [y+3]/2)
a) 1 = (x+8)/2
2 =x+8
x = -6
b) 3 = (y+3)/2
6 = y+3
y = 3