Respuesta :

The chemical reaction would be written as:

2H2 + O2 = 2H2O

We are given the amounts of the reactants thus we need to determine the limiting reactant before determining how much product is produced.

4.0 g H2 ( 1 mol / 2.02 g ) = 1.98 mol H2
5.0 g O2 ( 1 mol / 32 g ) = 0.1563 mol O2

The limiting reactant would be O2 since it would be consumed completely in the reaction.

0.1563 mol O2 ( 2 mol H2O / 1 mol O2 ) ( 18.02 g / mol ) = 5.6 g H2O is produced

The mass of water produced is 5.6 g

The reaction is between hydrogen gas and oxygen molecules. Therefore,

Chemical reaction:

  • H₂ + O₂ → H₂O

Let's balance the reaction before calculating the mass of water produced.

2H₂ + O₂ → 2H₂O

The limiting reagent is oxygen and it will determine the amount of product formed. Therefore,

32 g of oxygen = 36 g of water

5 g of oxygen = ?

cross multiply

mass of water formed = 36 × 5 / 32

mass of water formed = 180 / 32

mass of water formed = 5.625 g

mass of water formed = 5.6 g

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