Answer:
(1,3) and (2,4).
Step-by-step explanation:
The inequality is [tex]y > -x^2+5[/tex], so
for (0,5):
[tex]5> -(0)^2+5[/tex]
[tex]5> 0+5[/tex]
[tex]5>5[/tex], that is false, then (0,5) is not in the solution set of [tex]y > -x^2+5[/tex].
for (1,3):
[tex]3> -(1)^2+5[/tex]
[tex]3> -1+5[/tex]
[tex]3>4[/tex], that is false, then (1,3) is not in the solution set of [tex]y > -x^2+5[/tex].
for (2,4):
[tex]4> -(2)^2+5[/tex]
[tex]4> -4+5[/tex]
[tex]4>1[/tex], that is true, then (2,4) is in the solution set of [tex]y > -x^2+5[/tex].
