[tex]\bf \textit{volume of a pyramid}\\\\
V=\cfrac{1}{3}Bh\qquad
\begin{cases}
B=base\\
h=height\\
----------\\
B=\frac{1}{4}B\\\\
h=\frac{1}{4}h
\end{cases}\implies 1536=\cfrac{1}{3}Bh
\\\\\\
V=\cfrac{1}{3}\cdot \cfrac{B}{4}\cdot \cfrac{h}{4}\implies V=\cfrac{1}{3}Bh\cdot \cfrac{1}{4\cdot 4}\implies V=\cfrac{1}{3}Bh\cdot \cfrac{1}{16}
\\\\\\
V=\cfrac{\frac{1}{3}Bh}{16}\impliedby \frac{1}{16}th\textit{ of the original}[/tex]
