Respuesta :

irspow
-x^2-6x-8=0

-x^2-2x-4x-8=0

-x(x+2)-4(x+2)=0

(-x-4)(x+2)=0

-(x+4)(x+2)=0

x=-4, -2 so the two solutions are the points (-4, 0), (-2, 0)

Answer:

Step-by-step explanation:

Hi there, every time we pick a function and instead of f(x) we place a 0. We've just turned it into an equation.

So that's the case.

[tex]0=-x^{2} -6x-8\\ x^{2} +6x+8=0\\[/tex]

As a=1, then the solution may also be found through another method. Which two numbers and their product is 8? And the same two number added gives us 6?

[tex]P(x)=4*2=8\\ S(x)=4+2=6\\[/tex]

As their opposite numbers to 4 and 2 so the Solution Set is

S={-4,-2}

We could find the solution through the Quadratic Formula as well

[tex]\frac{6+\sqrt{36-4(-1)(-8)}}{2*(-1)}\\\frac{6-2}{-2}=-2 ,\frac{6+2}{-2}=-4[/tex]

S={-4,-2}

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