Respuesta :
-x^2-6x-8=0
-x^2-2x-4x-8=0
-x(x+2)-4(x+2)=0
(-x-4)(x+2)=0
-(x+4)(x+2)=0
x=-4, -2 so the two solutions are the points (-4, 0), (-2, 0)
-x^2-2x-4x-8=0
-x(x+2)-4(x+2)=0
(-x-4)(x+2)=0
-(x+4)(x+2)=0
x=-4, -2 so the two solutions are the points (-4, 0), (-2, 0)
Answer:
Step-by-step explanation:
Hi there, every time we pick a function and instead of f(x) we place a 0. We've just turned it into an equation.
So that's the case.
[tex]0=-x^{2} -6x-8\\ x^{2} +6x+8=0\\[/tex]
As a=1, then the solution may also be found through another method. Which two numbers and their product is 8? And the same two number added gives us 6?
[tex]P(x)=4*2=8\\ S(x)=4+2=6\\[/tex]
As their opposite numbers to 4 and 2 so the Solution Set is
S={-4,-2}
We could find the solution through the Quadratic Formula as well
[tex]\frac{6+\sqrt{36-4(-1)(-8)}}{2*(-1)}\\\frac{6-2}{-2}=-2 ,\frac{6+2}{-2}=-4[/tex]
S={-4,-2}
