Respuesta :
f(x) = x^2 + 5x.......evaluate f(-2).....so sub in -2 everywhere there is an x
f(-2) = -2^2 + 5(-2)
f(-2) = 4 - 10
f(-2) = -6 <==
f(-2) = -2^2 + 5(-2)
f(-2) = 4 - 10
f(-2) = -6 <==