Answer:
The correct option is 4.
Step-by-step explanation:
Let the line AB divided into 7 equal parts.
It is given that point P partitions the directed line segment from A to B in 3:4. It means 3 parts are before P and 4 partes are after P.
It is given that point Q partitions the directed line segment from A to B in 4:3. It means 4 parts are before Q and 3 partes are after Q.
It is given that point R partitions the directed line segment from A to B in2:5. It means 2 parts are before R and 5 partes are after R.
It is given that point S partitions the directed line segment from A to B in 5:2. It means 5 parts are before S and 2 partes are after S.
From the below figure we can say that point S is closest to point B.
It is also written as
[tex]A<\frac{2}{7}<\frac{3}{7}<\frac{4}{7}<\frac{5}{7} <B[/tex]
[tex]A<R<P<Q<S<B[/tex]
Therefore option 4 is correct.
