Respuesta :
Answer:
6
Explanation:
Oxidation-reduction (redox) reactions are defined by the transfer of electrons.
Half-reactions
In order to balance a redox reaction, we should break the reaction into its half-reactions. A half-reaction is only one part of the redox reaction; either the oxidation or reduction part. In simple terms, a half-reaction only contains one of the species or elements.
Oxidation half-reaction:
- Mg(s) → Mg²⁺(aq) + 2e⁻
Reduction half-reaction:
- Al³⁺(aq) + 3e⁻ → Al(s)
Balancing the Reaction
Now, to balance the equation we need to make the number of electrons in each half-reaction equal. Just like when balancing charges, we need to multiply each half-reaction by some factor to make the electrons cancel out. In order to make the electrons cancel out, we need to multiply the oxidation reaction by 3 and the reduction reaction by 2.
- (Mg(s) → Mg²⁺(aq) + 2e⁻) * 3 = 3Mg(s) → 3Mg²⁺(aq) + 6e⁻
- (Al³⁺(aq) + 3e⁻ → Al(s)) * 2 = 2Al³⁺(aq) + 6e⁻ → 2Al(s)
Since the half-reactions are balanced, we know the real number of electrons that are transferred. In both half-reactions, 6 electrons are being transferred. This means, per mole of reaction 6 moles of electrons are transferred.
In the unbalanced reaction between Mg(s) and [tex]Al_3^+[/tex](aq) to form Al(s) and [tex]Mg_2+[/tex](aq), a total of 3 electrons are transferred.
To determine the number of electrons transferred in a redox reaction, we need to balance the equation and identify the changes in oxidation states of the elements involved. In this reaction, Mg is oxidized from its elemental state (oxidation state of 0) to [tex]Mg_2+[/tex](oxidation state of +2), while [tex]Al_3+[/tex] is reduced to Al (oxidation state of 0).
The balanced equation for the reaction is:
[tex]3Mg(s) + 2Al_3+(aq) - > 2Al(s) + 3Mg_2+(aq)[/tex]
From the balanced equation, we can see that 3 moles of Mg react with 2 moles of [tex]Al_3^+[/tex]. Each Mg atom loses 2 electrons to become [tex]Mg_2^+[/tex], so 3 moles of Mg transfer a total of 6 electrons. Similarly, each [tex]Al_3^+[/tex] ion gains 3 electrons to become Al, so 2 moles of [tex]Al_3^+[/tex] ions accept a total of 6 electrons.
Therefore, in the given reaction, a total of 3 electrons are transferred.
To learn more about unbalanced reaction refer:
https://brainly.com/question/29629110
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