a. Inversely proportional is an equation with two variables a and b such that when the value of a increases value of b decreases and vise versa. The inverse equation for the given question is [tex]c=\dfrac{k}{d}[/tex]
b. The value of the d is 2312 units when c is 68 units.
Given-
c and d vary inversely where d is 2 units and c is 17 units.
[tex]c\propto \dfrac{1}{d}[/tex]
Part A
Equation that models the variation:
To convert this proportion into an equation, multiply by a constant k and find the value of constant.
[tex]c=\dfrac{k}{d}[/tex]
This is the required equation, now solving further for the value of constant k,
[tex]c\times d=k[/tex]
[tex]k=c\times d[/tex]
[tex]k=17\times 2[/tex]
[tex]k=34[/tex]
Part B
Value of d when the value of c is 68 units.
By the inverse equation,
[tex]c=\dfrac{k}{d}[/tex]
[tex]68=\dfrac{34}{d}[/tex]
[tex]d=68\times 34[/tex]
[tex]d=2312[/tex]
Hence, the value of the d is 2312 units when c is 68 units.
For more about inverse follow the link given below,
https://brainly.com/question/13715269
