class consists of 55% boys and 45% girls. It is observed that 25% of the class are boys and scored an A on the test, and 35% of the class are girls and scored an A on the test. If a student is chosen at random and is found to be a girl, the probability that the student scored an A is

Respuesta :

if you add 55% and 45% the total is 100%   so 45/100 are girls.  35% of the girls scored and A  so 35/45  is the probability that it is a girl chosen or 7/9. the probability is 7 out of 9

The probability that a girl chosen scored A is ⁷/₉

Given;

number of boys in the class, = 55%

number of girls in the class, = 45%

number of the boys who scored A = 25%

number of girls who scored A = 35%

To find:

the probability that a girl chosen scored A

The fraction of the boys who score A:

[tex]= \frac{25}{55} = \frac{5}{11}[/tex]

The fraction of the girls who scored A:

[tex]= \frac{35}{45} = \frac{7}{9}[/tex]

Thus, the probability that a girl chosen scored A is ⁷/₉

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