In circle J with the measure of minor arc HK= 90°, find m/HLK.
L
K
D
J.
H

Answer:
45°
Step-by-step explanation:
You want the measure of inscribed angle HLK, given that arc HK is 90°.
The measure of an inscribed angle is half the measure of the arc it subtends.
∠HLK = 1/2(arc HK) = 1/2(90°)
∠HLK = 45°
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