Analyze the graph of a cannonball launched from the ground with an initial velocity of 144 feet per second. The cannonball reached its maximum height after 4.5 seconds. What was the maximum height the cannonball reached?

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Answer:

324 feet

Step-by-step explanation:

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PLZ MARK AS BRAINLIEST

The maximum height the cannonball reached is 264m

Maximum height of an object

Given the equation of the height expressed as h(t)= -16t^2+144t

At maximum height, thee veloicity of the object is zero, hence;

  • v(t) = -32t + 144

If the velocity of the object is zero, hence:

-32t + 144 =0

32t = 144

t = 4.5secs

h(4.5) = -16(4.5)^2 + 144(4.5)

h(4.5) = -384 + 648

g(4.5) = 264m

Hence the maximum height the cannonball reached is 264m

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