Janine inflated a ball to a radius of 18 cm and another ball to a radius of 12 cm.

How much greater was the volume of air in the larger ball than the smaller ball?

Use 3.14 to approximate pi. Round to the nearest hundredth if necessary.

Question

26-03-2017
Mathematics

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Janine inflated a ball to a radius of 18 cm and another ball to a radius of 12 cm.

How much greater was the volume of air in the larger ball than the smaller ball?

Use 3.14 to approximate pi. Round to the nearest hundredth if necessary.

Respuesta :

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Аноним Аноним · Answer 1 · 2017-03-26T19:43:44+02:00

The answer is 17,182.08 cm³

To calculate this we need to calculate the volume of each ball V2 - V1 = ?
The volume of a sphere with radius r is:
V = 4/3 π r³

Ball 1:
r1 = 18 cm
V1 = 4/3 * 3.14 * 18³
V1 = 24,416.64 cm³

Ball 2:
r2 = 12 cm
V2 = 4/3 * 3.14 * 12³
V2 = 7,234.56 cm³

How much more water is in the larger balloon than in the smaller balloon:
V2 - V1 = 24,416.64 cm³ - 7234.56 cm³
= 17,182.08 cm³

Hope this helps!

iikittytime iikittytime · Answer 2 · 2020-03-18T21:36:52+01:00

iikittytime iikittytime

18-03-2020

Answer: 17,182.08cm³

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Janine inflated a ball to a radius of 18 cm and another ball to a radius of 12 cm. How much greater was the volume of air in the larger ball than the smaller ball? Use 3.14 to approximate pi. Round to the nearest hundredth if necessary.

Respuesta :

Otras preguntas

Janine inflated a ball to a radius of 18 cm and another ball to a radius of 12 cm.

How much greater was the volume of air in the larger ball than the smaller ball?

Use 3.14 to approximate pi. Round to the nearest hundredth if necessary.