The given elements put into an equation using their symbols are as follows:
Pb + [tex]AgC_{2}H_{3}O_{2} [/tex] = [tex]Pb(II){(C_{2}H_{3}O_{2})_2}[/tex] + Ag
Since there are 2 Pb on the right side of the equation, you would change the coefficient of Pb on the left side to 2:
2Pb + [tex]AgC_{2}H_{3}O_{2} [/tex] = [tex]Pb(II){(C_{2}H_{3}O_{2})_2}[/tex] + Ag
Since there are 2 Acetate on the right side of the equation, you would change the coefficient of Silver Acetate on the left side to 2:
2Pb + [tex]2AgC_{2}H_{3}O_{2} [/tex] = [tex]Pb(II){(C_{2}H_{3}O_{2})_2}[/tex] + Ag
Now there are 2 Silver on the left side, so you change the coefficient of Silver on the right side to 2:
2Pb + [tex]2AgC_{2}H_{3}O_{2} [/tex] = [tex]Pb(II){(C_{2}H_{3}O_{2})_2}[/tex] + 2Ag
That is your final equation
The coefficients are 2 + 2 = 1 + 2
