we know that
If two lines are perpendicular, then the product of their slopes is equal to minus one
so
[tex]m1*m2=-1[/tex]
we have
[tex]J(0,2)\\K(3,1)\\L(1,-5)[/tex]
Remember that
the formula to calculate the slope between two points is equal to
[tex]m=\frac{(y2-y1)}{(x2-x1)}[/tex]
Step 1
Find the slope JK
we have
[tex]J(0,2)\\K(3,1)[/tex]
substitute in the slope's formula
[tex]m=\frac{(1-2)}{(3-0)}[/tex]
[tex]m=\frac{(-1)}{(3)}[/tex]
[tex]mJK=-\frac{1}{3}[/tex]
Step 2
Find the slope KL
we have
[tex]K(3,1)\\L(1,-5)[/tex]
substitute in the slope's formula
[tex]m=\frac{(-5-1)}{(1-3)}[/tex]
[tex]m=\frac{(-6)}{(-2)}[/tex]
[tex]mKL=3[/tex]
Step 3
Find the slope JL
we have
[tex]J(0,2)\\L(1,-5)[/tex]
substitute in the slope's formula
[tex]m=\frac{(-5-2)}{(1-0)}[/tex]
[tex]m=\frac{(-7)}{(1)}[/tex]
[tex]mJL=-7/tex]
Step 4
Verify if the sides of the triangle are perpendicular
Multiply the slopes
JK and KL
[tex]mJK=-\frac{1}{3}[/tex]
[tex]mKL=3[/tex]
[tex]-\frac{1}{3}*3=-1[/tex] ------> sides JK and KL are perpendicular
when verifying that it has two perpendicular sides, it is not necessary to continue verifying the others, since a triangle can only have a single right angle
therefore
the answer in the attached figure