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According to a rating survey, 49% of the households in a certain city tune in to the local evening TV news. If seven households are visited at random, what is the probability that three of them will have their television tuned to the local news? (Round your answer to five decimal places.)

Respuesta :

Use the binomial distribution with n=7, k=3, p=0.49 and q=1-p=1-0.49=0.51

[tex]P(k)= \frac{n!}{(n-k)!k!} p^{k}q^{n-k}= \frac{7!}{4!3!} 0.49^{3}0.51^{4}=0.2786[/tex]

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