Answer:
Mid point of 6 – 2i and –4 + 6i is 1+2i
A is correct.
Step-by-step explanation:
We are given two complex number and need to find mid point of them
[tex]z_1=a_1+ib_1\text{ and }z_2=a_2+ib_2[/tex]
[tex]\text{Mid point z}=\frac{z_1+z_2}{2}[/tex]
[tex]z=\frac{a_1+a_2}{2}+i\frac{b_1+b_2}{2}[/tex]
where, [tex]z_1=6-2i\text{ and } z_2=-4+6i[/tex]
Mid point of 6 – 2i and –4 + 6i
[tex]z=\frac{6-4}{2}+i\frac{-2+6}{2}[/tex]
[tex]z=1+2i[/tex]
Thus, Mid point of 6 – 2i and –4 + 6i is 1+2i
