An area reserved for a parking lot is 80 feet long and 77 feet wide. The stalls of the lot are at 90° angles to two one-way aisles. Each aisle is 80 feet by 10 feet. The three areas set aside for the parking spaces are congruent rectangles. Each parking space will be 19 feet by 8 feet. What is the maximum number of parking spaces that will fit in the lot?

well the parking spot columns are 80 feet long since they go all the way its length.

there are 2 columns which are 10 feet wide so we can talk out the 20 feet of aisle width. that would mean there is 77 - 20 feet of width for parking spots so 57 feet

the spots are 8 feet wide apiece and their width is parallel to the length of overall lot so there is up to 80 feet. So how many times does 8 feet fit into 80 feet. 10 times. So so we can have 10 spots for each row of spots.

each spot is 19 feet long and there are 3 rows of spots so 19 * 3 = 57. So they fit exactly 3

so we have 3 rows by 10 columns.
3*10 = 30 apots

bhoopendrasisodiya34 bhoopendrasisodiya34 · Answer 2 · 2022-02-22T06:55:58+01:00

An area reserved for a parking lot with two aisle row has maximum number of parking spaces that will fit in the lot is 30.

What is area of rectangle?

Area of rectangle is the product of the length of the rectangle and the width of the rectangle. It can be given as,

[tex]A=a\times b[/tex]

Here, (a)is the length rectangle and (b) is the width of the rectangle.

The length of the parking lot is 80 feet and the width of the parking lot is 77 feet.

Each aisle is 80 feet by 10 feet and each parking space will be 19 feet by 8 feet.

Total area of parking lot is,

[tex]A_p=80\times 77\\A_p=6160\rm ft^2[/tex]

Thus, total area of parking lot is 6160 feet squared.

As the each aisle is 80 feet by 10 feet. Thus, the total area of the one aisle is,

[tex]A_a=80\times10\\A_a=800\rm ft^2[/tex]

As there is two aisle row is there. Thus the total area by two aisle is,

[tex]A_a=2\times 800\\A_a=1600\rm ft^2[/tex]

The area remain for parking space is,

[tex]A=6160-1600\\A=4560\rm ft^2[/tex]

As the parking space will be 19 feet by 8 feet. Thus, the total area of the parking space is,

[tex]A_a=19\times8\\A_a=152\rm ft^2[/tex]

As the total parking area remain for parking space is 4560 squared feet and the total area of required for one parking space is 152 squared feet. Thus the maximum number of parking spaces that will fit in the lot is,

[tex]n=\dfrac{4560}{152}\\n=30[/tex]

Hence, maximum number of parking spaces that will fit in the lot is 30 lot.

Learn more about the area of rectangle here;

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