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A spring has a spring constant k of 88.0 N/m. How much must this spring be compressed to store 45.0 J of potential energy

Respuesta :

Answer:

The compression in the string is 1.011 m.

Explanation:

Given that,

Spring constant = 88.0 N/m

Potential energy = 45.0 J

We need to calculate the compression in the string

Using formula of elastic potential energy

[tex]U=\dfrac{1}{2}kx^2[/tex]

[tex]x=\sqrt{\dfrac{2U}{k}}[/tex]

Where, U = potential energy

k = spring constant

x = compression in the string

Put the value into the formula

[tex]x=\sqrt{\dfrac{2\times45.0}{88.0}}[/tex]

[tex]x=1.011\ m[/tex]

Hence, The compression in the string is 1.011 m.

asuwafohjames

The spring must be compressed by 1.01 m.

To calculate the compression of the spring, we use the formula below.

Formula:

  • E = ke²/2................. Equation 1

Where:

  • E = Energy stored in the spring
  • k = spring constant
  • e = Length of compression of the spring.

Make e the subject of the equation

  • e = √(2E/k)............ Equation 2

From the question,

Given:

  • E = 45 J
  • k = 88 N/m

Substitute these values into equation 2

  • e = √(2×45/88)
  • e = √(90/88)
  • e = √(1.023)
  • e = 1.01 m

Hence, The spring must be compressed by 1.01 m.

Learn more about spring's compression here: https://brainly.com/question/2901244

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