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There are two numbers, one is 7 more than twice the other. The sum of the numbers is 43. Make the equation to find the smaller number. Find the two numbers.

Respuesta :

susnk
The larger number is 2x + 7. The smaller number is x.

2x + 7 + × = 43

3x + 7 = 43

3x +7 -7 = 43 -7

3x = 36

3x/3 = 36/3

× = 12

checking...

2 (12) + 7 + 12 = 43

Answer:

The two numbers are 12,31.

I don't know the equation

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