Respuesta :
Rearrange the equation to standard form of a quadratic equation (ax^2+bx+c=0) by switching sides: 5x^2+2x-12=0. Now, use the quadratic equation formula to solve. You should come out with x_1=sqrt61-1/5 and x_2=-1+sqrt61/5. Thus, your answer is B, or two solutions.
Answer:
A. two solutions
Step-by-step explanation:
To find the number of real solutions the equation is having, we need to solve first;
0=5x²+2x-12
This equation can be re-written as;
5x²+2x-12 = 0
We will use the formula method to solve
Using formula method;
x = -b ±√b² - 4ac / 2a
From the equation given,
a = 5 b = 2 and c=-12
x = -2 ± √2² - 4(5)(-12) / 2(5)
x = -2 ± √4 + 240 / 10
x = -2/10 ± √244 /10
x = [tex]\frac{-1}{5}[/tex] ± 1.56
x = - 0.2 ± 1.56
Either x = -0.2 + 1.56 or x = -0.2 - 1.56
Either x = 1.36 or x = -1.76
Therfore, this equation have two real number solutions
