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An engineer designs a satellite dish with a parabolic cross section. The dish is 16 ft wide at the​ opening, and the focus is placed 6 ft from the vertex. ​
a) Position a coordinate system with the origin at the vertex and the​ x-axis on the​ parabola's axis of symmetry and find an equation of the parabola.
​b) Find the depth of the satellite dish at the vertex.

Respuesta :

Hagrid
We are given
width = 16 ft
focus = 6 ft from the vertex

The equation of the parabola is
y = 4ax^2
a = 6
y = 4(6) x^2
y = 24 x^2

The depth of the satellite dish is
y = 24 (16/2)^2
y = 1536 ft