2AlCl3 --> 2Al + 3Cl2

If 10.0g of aluminum chloride are decomposed, how many molecules of Cl2 are produced?

Plz help :(

Respuesta :

0.1125 moles

Total mass number of AlCl3 = 27 + (3x35.5) = 133.5

Number of moles equals mass divided by mass number

10:133.5=0.075 ( this is the number of moles of AlCl3)

To get the number of moles of Cl2, look at the coefficient of both AlCl3 and Cl2

0.075x3:2=0.1125 moles

I hope this helps