A straight line inserted at the origin terminates at the point (6, 7) as it sweeps out an angle θ in the standard position rhus the evaluation of sinθ 7sqrt85/85.
Trigonometric ratios for a right-angled triangle are from the perspective of a particular non-right angle.
In a right-angled triangle, two such angles are there which are not right angled(not of 90 degrees).
The slanted side is called the hypotenuse.
A straight line inserted at the origin terminates at the point (6, 7) as it sweeps out an angle θ in the standard position.
We have x=6 and y=7
We'll need to solve for the hypotenuse to find the trigonometric func.
[tex]h^2=x^2+y^2\\h=\sqrt{x^2}+y^2\\h=\sqrt{36}+49\\h=\sqrt{85}[/tex]
Therefore,
[tex]sin\theta= \dfrac{opposite}{ hypotenuse}[/tex]
[tex]sin\theta= \dfrac{7}{ \sqrt{85} }[/tex]
Learn more about trigonometric ratios here:
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