Answer:
[tex]\text{probability of banana}\frac{1}{6}[/tex]
[tex]\text{probability of not ace}=\frac{12}{13}[/tex]
Step-by-step explanation:
Question 1:
Total of 48 cards and 8 card of each fruit
[tex]Probability =\frac{\text{favourable outcomes}}{\text{total number of outcomes}}[/tex]
On substituting the values in the formula we will get
[tex]Probability =\frac{8}{48}=\frac{1}{6}[/tex]
Required probability is [tex]\frac{1}{6}[/tex]
Question 2:
Total number of ace is 4
Total number of cards is 52
[tex]Probability =\frac{\text{favourable outcomes}}{\text{total number of outcomes}}[/tex]
On substituting the values in the formula we will get
[tex]Probability =\frac{4}{52}=\frac{1}{13}[/tex]
Probability of ace + probability of not ace =1
Hence, [tex]\text{probability of not ace}=1-\frac{1}{13}[/tex]
[tex]\text{probability of not ace}=\frac{12}{13}[/tex]
