Respuesta :
Radius: 6
Move all variables to the left side and all constants to the right side.(x−4)2+(y−3)2=36x-42+y-32=36This is the form of a circle. Use this form to determine the center and radius of the circle.(x−h)2+(y−k)2=r2
Move all variables to the left side and all constants to the right side.(x−4)2+(y−3)2=36x-42+y-32=36This is the form of a circle. Use this form to determine the center and radius of the circle.(x−h)2+(y−k)2=r2
The center of the circle (x - 3)^2 + (y + 3)^2 = 36 The Radius is 6 and the center would be (-3, 3).
What is the equation of the circle with radius r units, centered at (x,y) ?
If a circle O has a radius of r units length and it has got its center positioned at (h, k) point of the coordinate plane, then, its equation is given as:
[tex](x-h)^2 + (y-k)^2 = r^2[/tex]
Use this form to determine the center and radius of the circle.
[tex](x-h)^2 + (y-k)^2 = r^2[/tex]
By comparing both the equation
[tex](x - 3)^2 + (y + 3)^2 = 36\\\\ (x - 3)^2 + (y + 3)^2 = 6^2.[/tex]
r² = 36 ... r = 6
thus the center would be (-3, 3).
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