Respuesta :
since the collision is elastic the kinetic energy in the beginning is the same after the collision. K1+K2. kinetic energy is given by [tex] \frac{1}{2}m v^{2} [/tex]
The total is given by
[tex] \frac{1}{2} m_{1} ( v_{1} )^{2}+ \frac{1}{2} m_{2} ( v_{2} )^{2} [/tex]
This gives 19.26J. So the first answer looks to be the right one
The total is given by
[tex] \frac{1}{2} m_{1} ( v_{1} )^{2}+ \frac{1}{2} m_{2} ( v_{2} )^{2} [/tex]
This gives 19.26J. So the first answer looks to be the right one
Answer:
19.3
Explanation:
Just a quick answer the other guy says the same thing