Respuesta :

irspow
It depends on the value of the discriminant of the quadratic.  

If you are familiar with the quadratic formula...

x=(-b±√(b^2-4ac))/(2a)

The part under the radical sign (b^2-4ac) is called the discriminant of the quadratic  (of the form ax^2+bx+c)

If the discriminant is less than zero there are no REAL solutions  (however there are two imaginary solutions)

If the discriminant is equal to zero, there is just one solution

If the discriminant is greater than zero, there are two real solutions.

So depending on context, if you are to exclude imaginary solutions (which we often do) you can have 0,1, or 2 real solutions.

However you will NEVER have three solutions. (real or imaginary)

Answer with explanation:

→An equation of the type

  A x² + B x +C=0

is called Quadratic equation.

→The greatest degree of the Quadratic function is, 2 .So, it has Maximum of two roots.

→An ,equation of the type,

A x² + B=0 , is also Quadratic.

It has two roots which are equal.

→You can also get, also, 0 number of  solution or roots, which are both complex or Imaginary.

The Quadratic function can't have , 3 , roots.

Option D: 3