A water tank is being drained at a steady rate. The initial level of the water in the tank was 5.5 feet. The graph below shows the water level over time as the tank is drained

The slope of the line graphed which shows the water level over time as the tank is drained at a steady rate is 1/2.
The equation of the line is the way of representation of a line in the equation form. The equation of the line can be given as,
[tex]y=mx+c[/tex]
Here, (m) is the slope of the line and (c) is the y intercept.
The slope of the line can be found out using the following formula.
[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
Here, (x,y) is the coordinate points.
A water tank is being drained at a steady rate. The initial level of the water in the tank was 5.5 feet.
At this initial level, the value of time is 0. Thus, the coordinates of this point are (0,5.5). After 1 hour, the water level is 5 feet. Thus, the coordinates of this point are (1, 5).
The slope of the line, with these two point, can be given as,
[tex]m=\dfrac{5-5.5}{1-0}\\m=\dfrac{0.5}{1}[/tex]
Multiply and divide by 10,
[tex]m=\dfrac{0.5\times10}{1\times10}\\m=\dfrac{5}{10}\\m=\dfrac{1}{2}[/tex]
Thus, the slope of the line graphed which shows the water level over time as the tank is drained at a steady rate is 1/2.
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