[tex]\bf log_4(x-2)+log_4(5)=log_4(70)\\\\
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log_{{ a}}(xy)\implies log_{{ a}}(x)+log_{{ a}}(y)\\\\
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log_4[5(x-2)]=log_4(70)\impliedby \textit{take out the } log_4 \textit{ from both sides}
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5(x-2)=70\implies x-2=\cfrac{70}{5}\implies x-2=14\implies x=16[/tex]