[tex]\bf \begin{array}{lclll}
\ \textless \ &-4&,&27\ \textgreater \ \\
&\uparrow &&\uparrow \\
&a&&b
\end{array}\qquad tan(\theta)=\cfrac{b}{a}\implies \measuredangle \theta=tan^{-1}\left( \frac{b}{a} \right)
\\\\\\
\measuredangle \theta=tan^{-1}\left( \frac{27}{-4} \right)[/tex]
