Answer: A. [tex](x-1)(x+4)=0[/tex]
Step-by-step explanation:
Given equation : [tex]x^2 + 3x - 4 = 0[/tex]
We can rewrite the above equation as :
[tex]x^2 + 3x - 4 = 0\\\\x^2+(4x-x)-4=0\\\\ [/tex]
Which can be rewritten as :
[tex]x^2+(-x+4x)-4=0[/tex]
i.e.
[tex]x^2-x+4x-4=0[/tex]
Take x common from first two terms and 4 from last two terms , we get
[tex]x(x-1)+4(x-1)=0[/tex]
Take (x-1) common from both terms , we get
[tex](x-1)(x+4)=0[/tex]
Thus, the correct factored form of the given equation :
A. [tex](x-1)(x+4)=0[/tex]
