Respuesta :
complete the square on the terms in x and y:-
(x - 2)^2 + (y + 1)^2 - 4 - 1 - 11 = 0
(x - 2)^2 + (y + 1)^2 = 16
So the centre is at (2,-1) and the radius = sqrt 16 = 4
(x - 2)^2 + (y + 1)^2 - 4 - 1 - 11 = 0
(x - 2)^2 + (y + 1)^2 = 16
So the centre is at (2,-1) and the radius = sqrt 16 = 4