Answer:
16 ft.
Step-by-step explanation:
We have been given that the length of each hay bale is 4 ft and the width of each hay bales is [tex]1\frac{1}{3}=\frac{4}{3}[/tex] ft. We are also given that the volume of each hay bale is [tex]10\frac{2}{3}=\frac{32}{3}[/tex] cubic ft.
We will use volume of cuboid formula to find the height of each bale.
[tex]\text{Volume of cuboid}=l\cdot w\cdot h[/tex], where,
l = Length of cuboid,
w = Width of cuboid,
h = Height of cuboid.
Upon substituting our given values in above formula we will get,
[tex]\frac{32}{3}=4\cdot \frac{4}{3}\cdot h[/tex]
[tex]\frac{32}{3}=\frac{16}{3}\cdot h[/tex]
Upon multiplying both sides of our equation by [tex]\frac{3}{16}[/tex] we will get,
[tex]\frac{32}{3}\times \frac{3}{16}=\frac{16}{3}\times \frac{3}{16}\cdot h[/tex]
[tex]2=h[/tex]
Since we are asked to find the height of 8 hay bales stacked on each other, so we will multiply height of each hay bale by 8.
[tex]\text{Height of 8 hay bales}=8\times 2=16[/tex]
Therefore, the height of the stacked hay bales is 16 feet.
