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Given that ∠MQL = 180° and ∠XQR = 180°, which equation could be used to solve problems involving the relationships between ∠XQL and ∠MQR?
A) (48 + 1b) = (54 − 1b)
B) (48 + 1b) + (54 − 1b) = 180
C) (54 − 1b) − (48 + 1b) = 180
D) (54 − 1b) − 180 = (48 + 1b)

Given that MQL 180 and XQR 180 which equation could be used to solve problems involving the relationships between XQL and MQR A 48 1b 54 1b B 48 1b 54 1b 180 C class=

Respuesta :

The answer will be A which is (48+1b)=(54-1b). Hope it help!

Given

∠MQL = 180° and ∠XQR = 180°

Find out which equation  be used to solve problems involving the relationships between ∠XQL and ∠MQR.

To proof

Vertically opposite angle

The angles opposite each other when two lines cross. They are always equal.

As shown in the diagram

∠XQL, ∠MQR are vertically opposite angle.

∠XQL = ∠MQR

(48 +1b) = (54 - 1b)

The problem used to solve problems involving the relationships between ∠XQL and ∠MQR  is (48 +1b) = (54 - 1b).

option ( A) is correct.

Hence proved  




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