Respuesta :
The gram molecular mass of [tex]\text{CO}_2[/tex] is the same as the gram molecular mass of [tex]\boxed{4.)\;\text{C}_3\text{H}_8}[/tex].
Further Explanation:
Gram molecular mass is the mass of one mole of the substance in grams. It is similar to molar mass.
The molar mass of [tex]\text{CO}_2[/tex] can be calculated as follows:
[tex]\text{Molar mass of}\;\text{CO}_2=[1(\text{Atomic mass of})+2(\text{Atomic mass of O})][/tex] …… (1)
Substitute 12.01 g for the atomic mass of C and 15.99 g for the atomic mass of O in equation (1).
[tex]\begin{aligned}\text{Molar mass of}\;\text{CO}_2&=[1(12.01\;\text{g})+2(15.99\;\text{g})]\\&=43.99\;\text{g/mol}\\&\approx44\;\text{g/mol}\end{aligned}[/tex]
1.) The molar mass of CO can be calculated as follows:
[tex]\text{Molar mass of CO}=[1(\text{Atomic of mass C})+1(\text{Atomic mass of O})][/tex] …… (2)
Substitute 12.01 g for the atomic mass of C and 15.99 g for the atomic mass of O in equation (2).
[tex]\begin{aligned}\text{Molar mass of CO}&=[1(12.01\;\text{g})+1(15.99\;\text{g})]\\&=28\;\text{g/mol}\end{aligned}[/tex]
2.) The molar mass of [tex]\text{SO}_2[/tex] can be calculated as follows:
[tex]\text{Molar mass of}\;\text{SO}-2=[1(\text{Atomic mass of S})+2(\text{Atomic mass of O})][/tex] …… (3)
Substitute 32.07 g for the atomic mass of S and 15.99 g for the atomic mass of O in equation (3).
[tex]\begin{aligned}\text{Molar mass of}\;\text{SO}_2&=[1(32.07\;\text{g})+2(15.99\;\text{g})]\\&=64.05\;\text{g\mol}\end{aligned}[/tex]
3.) The molar mass of [tex]\text{C}_2\text{H}_6[/tex] can be calculated as follows:
[tex]\text{Molar mass of}\;\text{C}_2\text{H}_6=[2(\text{Atomic mass of C})+6(\text{Atomic mass of O})][/tex] …… (4)
Substitute 12.01 g for the atomic mass of C and 1.008 g for the atomic mass of H in equation (4).
[tex]\begin{aligned}\text{Molar mass of}\;\text{C}_2\text{H}_6&=[2(12.01\;\text{g})+6(1.008\;\text{g})]\\&=30.068\;\text{g/mol}\end{aligned}[/tex]
4.) The molar mass of [tex]\text{C}_3\text{H}_8[/tex] can be calculated as follows:
[tex]\text{mollar mass of}\;\text{C}_3\text{H}_8=[39(\text{Atomic mass of C})+8(\text{Atomic mass of H})][/tex] …… (5)
Substitute 12.01 g for the atomic mass of C and 1.008 g for the atomic mass of H in equation (5).
[tex]\begin{aligned}\text{Molar mass of}\;\text{C}_3\text{H}_8&=[3(120.1\;\text{g})+8(1.008\;\text{g})]\\&=44.094\;\text{g/mol}\\&\approx44\;\text{g/mol}\end{aligned}[/tex]
Therefore the gram molecular mass of [tex]\text{CO}_2[/tex] is the same as that of [tex]\text{C}_3\text{H}_8[/tex].
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Answer details:
Grade: Senior School
Chapter: Mole concept
Subject: Chemistry
Keywords: gram molecular mass, atomic mass, molar mass, CO2, CO, C3H8, C2H6, SO2.
The mass or the weight of the given mixture or compound is called molecular mass and is measured in Daltons. It is represented as m.
The following will have the same molecular mass as [tex]\rm CO_{2}[/tex]:
Option 4.) [tex]\rm C_{3}H_{8}[/tex]
The molecular mass will be estimated as:
The molar mass of Carbon dioxide can be calculated by the following formula:
[tex]\text{The molar mass of CO}_{2} & = [1 (\text{Atomic mass of C} ) + 2( \text{Atomic mass of O})][/tex]
- Atomic Mass of C = 12.01 g
- Atomic Mass of O = 15.99 g
Substituting values :
[tex]\begin{aligned} \text{Molar Mass (m) of CO}_{2} & = [1 (12.01) + 2( 15.99 )]\\\rm m & = 43.99 \;\text{g/mol}\\\rm m & = 44 \;\text{g/mol} \end{aligned}[/tex]
1. The Molar mass of CO can be estimated as:
[tex]\begin{aligned}\text{The molar mass of CO} & = [1 (\text{Atomic mass of C} ) + ( \text{Atomic mass of O})] \end{aligned}[/tex]
- Atomic Mass of C = 12.01 g
- Atomic Mass of O = 15.99 g
Substituting values in equation:
[tex]\begin{aligned} \text{Molar Mass (m) of CO} & = [1 (12.01) + 1( 15.99 )]\\\text{m} &= 28 \rm \;g/mol}\end{aligned}[/tex]
2.The molar mass of [tex]\rm SO_{2}[/tex] will be estimated as:
[tex]\begin{aligned} \text{The molar mass of SO}_{2} = \text{[1 (Atomic mass of S ) + 2( Atomic mass of O)]} \end{aligned}[/tex]
- Atomic Mass of S = 23.07 g
- Atomic Mass of O = 15.99 g
Substituting values in equation:
[tex]\begin{aligned} \text{The molar mass of SO}_{2} &= \text{[1 (23.07 ) + 2( 15.99)]} \\\text{m} &= 64.05 \text{g/mol} \end{aligned}[/tex]
3.The molar mass of [tex]\rm C_{2}H_{6}[/tex] will be estimated as:
[tex]\begin{aligned} \text{Molar mass of C}_{2}\rm H_{6} & = [2 (\rm Atomic \;mass \;of \;C) + 6( \text{Atomic mass of H})] \end {aligned}[/tex]
- Atomic Mass of C = 12.01 g
- Atomic Mass of H = 1.008 g
Substituting values in equation:
[tex]\begin{aligned} \text{Molar mass of C}_{2}\rm H_{6} & = [2 (\rm Atomic \;mass \;of \;C) + 6( \text{Atomic mass of H})] \\\rm m &=30.068 \; \rm g/mol \end {aligned}[/tex]
4.The molar mass of [tex]\rm C_{3}H_{8}[/tex] will be estimated as:
[tex]\begin{aligned} \text{Molar mass of C}_{3}\rm H_{8} & = [ 3 (\rm Atomic \;mass \;of \;C) + 8( \text{Atomic mass of H})] \end {aligned}[/tex]
- Atomic Mass of C = 12.01 g
- Atomic Mass of H = 1.008 g
Substituting values in equation:
[tex]\begin{aligned} \text{Molar mass of C}_{3}\rm H_{8} & = [ 3 (\rm 12.01) + 8( \text{1.008})] \\\rm m & = 44.094 \rm \;g/mol\\\rm m &= 44 \rm \;g/mol \end {aligned}[/tex]
Therefore, the molar mass of carbon dioxide is equal to [tex]\rm C_{3}H_{8}[/tex].
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