A cube of aluminum (Cp = 0.897 J/g•K) has a temperature of 325 K. It is placed in a beaker of cold water. If the aluminum cools to 301 K as the water absorbs 815.7 J of heat, what is the mass of the cube?

Respuesta :

Answer: 37.9 g

Explanation:

heat gained = heat lost

[tex]Q= m\times c\times \Delta T[/tex]

Q = heat lost by aluminium= heat gained by water= 815.7 J

m = mass of the substance = ?

c = heat capacity of  aluminium = 0.897 J/gK      

[tex]\Delta T={\text{Change in temperature}}=(325-301)K= 24[/tex]  [tex]815.7J=m\times 0.897J/gK\times24K[/tex]

[tex]m=37.9g[/tex]



A cube of aluminum has a temperature of 325 K, if the aluminum cools to 301 K as the water absorbs 815.7 J of heat then the mass of cube is 37.9 grams.

How do we calculate the mass?

Mass of the aluminum cube will be calculated by using the below formula:

Q = mcΔT, where

Q = amount of absorbed heat = 815.7 J

m = mass of aluminum cube = ?

c = specific heat of aluminum cube = 0.897 J/g•K

ΔT = change in temperature = 325 - 301 = 24K

On putting values we get

m = 815.7 / (0.897)(24)

m = 37.9g

Hence mass of aluminum cube is 37.9 g.

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https://brainly.com/question/488376