Answer:
v = 0.5 m/s
Explanation:
It is given that ,
Initially april swims 50 meter north so distance travelled by her in north direction [tex]d_{north}=50\ m[/tex]
Then she turns 20 meter south so distance travelled by her in south direction is [tex]d_{south}=20\ m[/tex]
Time taken by her [tex]t=60\ s[/tex]
We need to find the velocity she travelled with.
Therefore, velocity [tex]v=\dfrac{displacement\ travelled}{time\ taken\ to\ travel\ the\ displacement}[/tex] equation 1..
We know displacement is given as distance between final position and initial position.
As we know april first move 50 m north from its initial position and came back 20 m south.
So, displacement by april is given is [tex]d=d_{north}-d_{south}=30 m[/tex]
Putting values of displacement covered and time taken in equation 1 ,we get [tex]v=\dfrac{30}{60}=0.5\ m/s[/tex]
Hence this is the required solution.
