Respuesta :

ANCKPOP
[tex] \left \{ {{y=x^2-2x-19} \atop { y+4x=5}} \right. [/tex]

[tex]*y+4x=5 \\y = 5-4x \\\\ *y=x^2-2x-19 \\( 5-4x)=x^2-2x-19 \\x^2-2x-19-5+4x=0 \\x^2+2x-24=0 \\(x+6)(x-4)=0 \\x+6=0 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x-4=0 \\x=-6 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x=4 \\\\ *y+4x=5 \\y+4(-6)=5 \\y-24=5 \\y=5+24 \\y=29 \\\\ This \ solution \ is \ (-6,29) \\\\ *y+4x=5 \\ y+4(4)=5 \\y+16=5 \\y=5-16 \\y=-11 \\\\ This \ solution \ is \ (4,-11) [/tex]


The answer is (-6, 29) and (4, -11)

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