Answer with explanation:
When we toss a coin,
Probability of getting Head
[tex]=\frac{1}{2}[/tex]
Probability of getting Tail
[tex]=\frac{1}{2}[/tex]
when we flip a coin three times, we can get maximum of three heads
X=0 T, 1 T, 2 T, 3 T, that is maximum of 3 tails.
We have to estimate ,the probability of tails coming up fewer than 2 times in 3 coin flips as T is represented by 1,and Head is represented by 0.
Means, X=0,1→→Probability Distribution
Out of 15 trials, in a simulation ,there are 6 trials in which[ there is tails coming up fewer than 2 times ,=either 1 Tail or 0 tail] .
={(000), (000), (010),(100),(000),(000)}
[tex]=\frac{6}{15}=\frac{2}{5}[/tex]
