Start by using trig to find the length of the line LJ
The triangle KJL (big right angled triangle) has been given the following dimensions
Hypotenuse = [tex]8 \sqrt{2} [/tex]
The adjacent angle is 30 degrees
Since we have the hypotenuse and the angle we must use the equation
opposite = Sin(angle) x Hypotenuse
Opposite= sin30 x [tex]8 \sqrt{2} [/tex]
Opposite= [tex]4 \sqrt{2} [/tex]
Therefore line LJ is [tex]4 \sqrt{2} [/tex]
Now look at the smaller right angled triangle (LMJ)
Hypotenuse is the line LJ which is [tex]4 \sqrt{2} [/tex]
The adjacent angle is 45
Since we have hypotenuse and angle we must use the equation opposite = sin(angle) * h
therefore
x= [tex]4 \sqrt{2} [/tex] * sin45= 4
