Answer:
599.5 m
Explanation:
The gain in gravitational potential energy of the man is given by:
[tex]\Delta U=mg\Delta h[/tex]
where
m is the man's mass
g is the gravitational acceleration
[tex]\Delta h[/tex] is the change in height of the hiket
In this problem, we have the following data:
U = 470,000 J
g = 9.8 m/s^2
m = 80 kg
Solving the formula for [tex]\Delta h[/tex], we find:
[tex]\Delta h = \frac{U}{mg}=\frac{470,000}{(80)(9.8)}=599.5 m[/tex]
The height of the hiker is 599.5 m. The energy is stored in an object or body due to its height above the ground.
It is the energy stored in an object or body due to its height above the ground.
[tex]U_g = mgh[/tex]
Where
[tex]U_g[/tex] - gravitational potential energy = 470,000 J
[tex]g[/tex] - gravitational acceleration = 9.8 m/s^2 9.8 m/s²
[tex]m[/tex] - mass = 80 kg
Put the values in the formula,
[tex]U_g = 80 \times 470,000 \times 9.8 \\\\U_g = 599.5 \rm \ m[/tex]
Therefore, the height of the hiker is 599.5 m.
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