Answer:
Juanita is standing 31.17 ft far from the tree.
Step-by-step explanation:
Angle of elevation measured by Juanita = [tex]\theta=30^o[/tex]
Height of the tree = 18 ft
Also, an image of that tree whose height is 18 ft and its top is making an angle of 30°.This means length of the image is equal to the distance at which Juanita is standing.
In fig ΔABC
[tex]\frac{AB}{BC}=\tan\theta[/tex]
[tex]\frac{18 ft}{BC}=\tan 30^o=0.5773[/tex] (tan 30° = 0.5773)
BC = 31.17 ft ≈ 31.2 ft
Juanita is standing 31.2 ft far from the tree.
