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A cannon shell is fired straight up from the ground at an initial speed of 225 m/s. After how much time is the shell at a height of 6.20 x 102 m above the ground and moving downward?

Respuesta :

UnicornFudge
█ Explanation █

✦ Use the equation y(t) = y₀ + v₀t + ½at²  to find the time. 
✦ Plug in the values of the equation.
✦ 620 = 225t - 4.9t² 
✦ Reorder the equation to form it into the quadratic formula. 
✦ 4.9t² - 225t + 620 = 0 
✦ Solve for t 
✦ t = 43

It will take 43 seconds for the shell above the ground.

Hope that helps! ★ If you have further questions about this question or need more help, feel free to comment below or leave me a PM. -UnicornFudge aka Nadia
asuwafohjames

The time taken for the shell to reach the maximum height is 5.56s.

The time taken for the shell to reach the maximum height can be calculated using the formula below.

Formula:

  • H = (v+u)t/2.............. Equation 1

Where:

  • H = maximum height reached by the shell
  • v = Final velocity
  • u = initial velocity
  • t = time taken.

make t the subject of the equation

  • t = 2H/(v+u)............. Equation 2

From the question,

Given:

  • H = 620 m
  • v = 0 m/s (at the maximum height)
  • u = 225 m/s.

Substitute these values into equation 2

  • t = 2(625)/(225+0)
  • t = 1250/2255
  • t = 5.56 s

Hence, The time taken for the shell to reach the maximum height is 5.56s

Learn more about maximum height here: https://brainly.com/question/12446886

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