Answer:
Option A is correct that is 64 leaves would be there.
Step-by-step explanation:
Total Number of ties = 8
Total number of shirts = 2
Total number of jackets = 4
No of ties have to be chosen = 1
No of shirt have to be chosen = 1
No of jacket have to be chosen = 1
we use combination to find number of ways,
[tex]^{n}\textrm{C}_{r}=\frac{n!}{r!\,(n-r)!}[/tex]
No way of choosing a tie = [tex]^{8}\textrm{C}_{1}=\frac{8!}{1!\,(8-1)!}=\frac{8!}{1!\,7!}=8[/tex]
No way of choosing a shirt = [tex]^{2}\textrm{C}_{1}=\frac{2!}{1!\,(2-1)!}=\frac{2!}{1!\,1!}=2[/tex]
No way of choosing a jacket = [tex]^{4}\textrm{C}_{1}=\frac{4!}{1!\,(4-1)!}=\frac{4!}{1!\,3!}=4[/tex]
Total Number of ways of selection = 2 × 4 × 8 = 64
Therefore, Option A is correct that is 64 leaves would be there.
